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Setting Out Vertical Curves ExampleDesign a vertical curve 200 metres long connecting a rising gradient of 2% with a falling gradient of 1.33% which meet in a summit of RL 30.35m, and chainage 2752 metres. Give offsets at 40 metre intervals. Chainage of A = 2752 - 100 = 2652m. Chainage of B = 2752 + 100 = 2852m. RL of A = 30.35 - 2 x 100/100 = 28.35m. RL of B = 30.35 - 1.33 x 100/100 = 29.02m. Distance from A of the highest point
Height at distance x (A taken as datum)
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