Table Of Contents
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| l = f(x0) + ( | df | )x0 Dx + ( | d2f | )x0 Dx2 + higher order terms |
| dx | dx2 |
Ignoring second and higher order terms gives equation that is linear inDx:
| Dx = | l - f(x0) | ||
| ( | df | ) x0 | |
| dx | |||
To solve this equation several things are required:
f(x) = (x - 3)3 + ex = 15
Estimate: x0 = 2, f(x0) = 0.6389
Differentiate: f'(x) = 3(x - 3)2 + ex
Solve:
| Dx = | 15 - f(x0) | = | 15 - (x0 - 3)3 + ex0 | = 0.829 |
| f'(x0) | 3(x0 - 3)2 + ex0 |
Next estimate: x0 = x0 + Dx
= 2.829
Now, f(x0) = 16.923, continue procedure until f(x0)
is sufficiently close to 15
Because the solution must be iterated due to ignorance of higher order terms from the Taylor expansion, the computation of the derivatives does not need to be all that accurate - this allows some cheating to take place. Note that the reduced observation l - f(x) must be accurately computed. This applies to Least Squares adjustment as well.
Cx = E [(x - m)(x - m)t]
| x1 - m1 | ||
| = E ( | x2 - m2 | [x1 - m1,
x2 - m2 |
| xn - mn |
| E{(x1 - m1)2} | E{(x1 - m1)2(x2 - m2)2} | E{(x1 - m1)2(xn - mn)2} | |
| = E{(x2 - m2)2(x1 - m1)2} | E{(x2 - m2)2} | E{(x2 - m2)2(x2 - m2)2} | |
| E{(xn - mn)2(x1 - m1)2} | E{(xn - mn)2(x2 - m2)2} | E{(xn - mn)2} |
The definition of variance of : xi : s2xi = E [( xi - mi )2]
The square root of the variance of x (= sxi) is the standard error or standard deviation of x
The definition of covariance of xi and xj : sxixj = E [( xi - mi )( xi - mj ) ]
Using these definitions:
| Cx = | s2x1 | sx1x2 | sx1xn | |
| sx1x2 | s2x2 | sx2xn | ||
| sxnx1 | sxnx2 | s2xn |
The coefficient of correlation is used to express the strength of dependence of one variable on another:
| rij = | sxiyj |
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| sxi sxj |
r has a range [-1, 1], where +1 indicates total correlation, and 0 indicates nor correlation at all.
As part of a least squares solution a weight matrix of observations can be used to indicate some observations are more or less precise than others, and some observations are correlated with others. A weight matrix of observations (P1) is the inverse of the covariance matrix of the observations:
P1 = C-11
In some circumstances C1 is diagonal (or assumed to be diagonal) since this makes the formation of the least squares solution simpler - e.g. forming P1 is simple.
Using the relationship between mean and expected value (shown previously):
my = E(y) = E(Ax) = AE(x) = Amx
Using the definition of the covariance matrix (also shown previously)
Cy = E{(y - my)(y - my)t}
= E{(Ax - Amx)(Ax - Amx)t}
= AE{(x - mx)(x - mx)t}At
= ACxAt
y = Ax
Cy = ACxAt (propagation of variance)

Measured: 3 directions measured with equal precision sd (not correlated) to give 2 angles.
| Equation: |
a1 |
= |
-1 1 0 |
d1 | say y = Ax |
| d2 | |||||
| d3 |
| Precisions: | Cx = s2d I | ||||
| Cy = |
-1 1 0 0 -1 1 |
s2d 0 0 -1 0 0 s2d 0 1 -1 0 0 s2d 0 1 |
= |
2s2d -s2d -s2d 2s2d |
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Notes:
| The correlation coefficient (see previous) is | - s2d | = | - 1 | , quite large. |
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| 2s2d | 2 |
Some survey network adjustment programs use angles and ignore the correlation, the general claim being that in a network with strong geometry the ignorance of the correlation has negligible effect on the end result. Other programs use either angles with correlations, or directions (no reduction to angles at all) their claim being the correlation between angles is significant and should not be ignored.
Bx = l + v
B - design matrix
x - unknown parameters (increments to the assumed coordinates)
l - observations
v - residuals
Cl = P-1l - Covariance matrix of the observations
Cx - Covariance matrix of the parameters
^ - least squares estimate of the parameter beneath
Without to much regard for detail at this stage, the solution via least squares is:
x = (BtPlB)-1BtPll
C
by propagation of variance is:
C
= [(BtPlB)-1BtPl]
Cl [(BtPlB)-1BtPl]
C
= [(BtPlB)-1Bt] [PlB
(BtPlB)-1]
C
= (BtPlB)-1 [BtPlB
] [BtPlB]-1
C
= (BtPlB)-1