Table Of Contents
Least Squares And Survey NetworksMathematical justification for the use of least squares will be given in the maths course, however least squares:
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| Dx1 | = | + | ||||||||||||
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| ff1 | ff1 | ff1 | ff1 | ff1 | ff1 | ff1 | ff1 | ff1 | Dz1 | |||||
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| fx1 | fy1 | fz1 | fx2 | fy2 | fz2 | fxm | fym | fzm | Dx2 | m1 - c1 | v1 | |||
| ff2 | ff2 | ff2 | ff2 | ff2 | ff2 | ff2 | ff2 | ff2 | Dy2 | m2 - c2 | v2 | |||
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| fx1 | fy1 | fz1 | fx2 | fy2 | fz2 | fxm | fym | fzm | Dz2 | |||||
| ffn | ffn | ffn | ffn | ffn | ffn | ffn | ffn | ffn | mn - cn | vn | ||||
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| fx1 | fy1 | fz1 | fx2 | fy2 | fz2 | fxp | fyp | fzp | Dxp | |||||
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| Dyp |
p - the number of unknown (x, y, z) points
n - the number of observations
mi - observation i
ci - value of observation computed with the assumed coordinates for observation i
vi - residual for observation i
f - function that expresses the observation as a function of the unknowns (coordinates), a different f is required for each different observation type
D - increments to the assumed coordinate values
Again without mathematical justification the least squares solution is based on minimising the weighted sum squares of the residuals:
vt Pmv = vt ( C-1m ) v = minimum
This gives a prescription:
Bt Pm v = 0
This leads to normal equations:
Bt Pm Bx = Bt Pm m
Nx = l
With N being the normal matrix. The solution is:
x = N-1 l = (Bt Pm B)-1 Bt Pm m
The covariance of the parameter estimates is given by the inverted normal matrix:
C
= N-1
Covariance matrices for the residuals and adjusted measurements are computed as (these matrices are required for statistical analysis of the adjustment results):
C
= BN-1Bt
C
= Cm - BN-1 Bt = Cm - C![]()